Question

огоороо 15. Write a balanced equation to show the reaction of gaseous ethane, C2H6, with gaseous oxygen to form carbon dioxide gas and water vapor. A. 2C2H.(g) + 702(g) + 4CO2(g) + 6H2O(g) B. CzH6(g) + 50(g) → 2CO(g) + 3H2O(g) C. 2CH.(g) + 502(g) + 4CO(g) + 6H2O(g) D. CzH6(g) + 70(g) 2C02(g) + 3H2O(g) E. CH.(g) + 302(g) + 2CO2(g) + 3H2O(g) Reaction Stoichiometry Answer the next two questions about the reaction

Answer 1

Answer Sheet:

When the ethane is reacted with oxygen produces carbon dioxide and water as products.

So the reaction is as follows

C2H6 (g) + O2 (g) -----> CO2(g) + H2O (g)

To balance this equation Start with the C atoms first and move to the H atoms next. It's easier to leave the O2 to the last, it has a way to alter the equation.

The equation become

C2H6 (g) + O2 (g) ------> 2 CO2 (g) + 3H2O (g)

Now we have to balance O2 in both side. This above equation the number of oxygen is odd. Since the oxygen is diatom Therefore, 14 would be the lowest common factor of 2 and 7. So the balanced equation become

2C2H6 (g) + 7O2 ------> 4CO2 (g) + 6H2O (g)

So the correct option is--

A. 2 C2H6 (g) + 7 O2(g) ---> 4CO2 (g) + 6H2O(g)