Option (b) is correct answer
If we write the formula for Calcium Phosphate
Calcium ion - Ca2+
Phosphate ion - PO43-
So the formula for Calcium Phosphate is Ca3(PO4)2
Hence option (b) would be correct
Select the correct solubility equilibrium for the slightly soluble salt, calcium phosphate. O CaPO4(s) -- Ca2+(aq)...
Question 24 1 pts Write the solubility product constant expression for calcium phosphate, Ca3(PO4)2 O [Ca2+][PO43-M[Ca3(PO4)2] O Ca2+1*[PO43-12 O [Ca2+][PO43-1 O [Ca2+12[PO43-13
Solutions of calcium hydroxide, Ca(OH)2, and sodium phosphate, Na3PO4, are mixed according to the following chemical equation. What is the ionic equation for the reaction The molecular equation is: 3Cu(OH)2(aq) + 2Na3PO4(aq) + Caz(PO4)2 (s) + NaOH(aq) 3Ca2+(aq) + 20H(aq) + 6Na*(aq) + PO43- (aq) - 3Ca2+ (aq) + PO43- (aq) + 6NaOH(aq) 3Ca2(aq) + OH2" (aq) + 2Na3aq) + PO43- (aq) - Ca3(PO4)2 (s) + 2Nazt (aq) + OH2" (aq) 3Ca2+ (aq) + 20H(aq) + 6Na*(aq) + PO43-lag) -...
Given that the solubility reaction for calcium phosphate is Ca3(PO4)2(s) = 3Ca2+ (aq) + 2PO43- (aq) why does the addition of acid increase the solubility of calcium phosphate? View Available Hint(s) O It decreases the phosphate ion concentration, forcing the equilibrium to the right It decreases the phosphate ion concentration, forcing the equilibrium to the left. O It increases the phosphate ion concentration, forcing the equilibrium to the right. It increases the phosphate ion concentration, forcing equilibrium to the left....
Question 4: Given the Ksp = 2.0 x 10-29 for the sparingly soluble salt, calcium phosphate (Ca3(PO4)2), determine the molar solubility of the salt in a solution that is 0.20 Min calcium perchlorate, Ca(CIO4)2.
(5 pts) If calcium cations and phosphate anions are each present at 0.20 mg/L in an aqueous solution, is the solid calcium phosphate expected to precipitate? See Table 2.3, p.62: Ca3(PO4)2(s) 3Ca+2(aq) + 2PO4-3(aq); Ksp=1.0x10-27. Molar masses: Ca3(PO4)2, 310.2; Ca+2, 40.1; PO4-3, 95.0.
A chemist fills a reaction vessel with 0.980 g calcium phosphate (Ca3(PO4)2) solid, 0.212 M calcium (Ca+2) aqueous solution and 0.119 M phosphate (PO4−3) aqueous solution at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy ΔG for the following chemical reaction: Ca3(PO4)2(s) 3Ca+2(aq)+2PO4−3(aq) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule.
QUESTION 1 1 points 1 points Save Answer Save Answer Calcium hydroxide is a slightly soluble salt. A saturated solution of calcium hydroxide is prepared, and comes to equilibrium: Ca(OH)2 (s) + Ca2+(aq) + 2 OH"(aq) What is the solubility product constant (Ksp) expression for this equilibrium? [Ca2+ [OH-] [Ca(OH)2] A. Ksp = B. Ksp = [Ca2+1OH-] c Ksp = [Ca2+[OH-] [caz+Com'] [Ca(OH)2] QUESTION 2 1 points Save Answer Consider a chemical reaction which has achieved a state of equilibrium....
what is the mass of calcium phosphate that can be prepared from 1.78g of Na3PO4? Na3PO4(aq) + Ca(OH)2 (aq)---> Ca3(PO4)(s)+NaOH(aq)
11:08 ..: LTE O < Question 17 of 29 Submit Which one of the following represents the net ionic equation for the reaction of Ca(NO3)2 with LizPO ? A) 3 Ca(NO3)2 (aq) + 2 Li3PO4 (aq) → Ca3(PO4)2 (s) + 6 NaNO3 (aq) B) Ca2+ (aq) + PO43- (aq) → Ca3(PO4)2 (s) C) 3 Ca2+ (aq) + 2 PO43- (aq) → Ca3(PO4)2 (s) D) Lit (aq) + NO3- (aq) → LINO3 (s)
QUESTION 2 Which of the following molecules will not be part of the equilibrium constant for this reaction: 4 Fe (s) + 3 02 (9) 2 Fe203 (s) Select all that apply Fe 02 Fe2O3 QUESTION 3 Which of the following molecules will not be part of the equilibrium constant for this reaction: Ca3(PO4)2 (s) = 3 Ca2+ (aq) + 2 PO43- (aq) Select all that apply Ca3(PO4)2 Ca2+ PO43-