Question

QUESTION 2 Which of the following molecules will not be part of the equilibrium constant for this reaction: 4 Fe (s) + 3 02 (9) 2 Fe203 (s) Select all that apply Fe 02 Fe2O3 QUESTION 3 Which of the following molecules will not be part of the equilibrium constant for this reaction: Ca3(PO4)2 (s) = 3 Ca2+ (aq) + 2 PO43- (aq) Select all that apply Ca3(PO4)2 Ca2+ PO43-

Answer 1

$\bf QUESTION\;2$

$\bf \text{ The active mass of } solids\text{ is taken to be }unity\text{ in the expression of equilibrium constant}$$\bf 4Fe(s)+3O_2(g)\rightleftharpoons Fe_2O_3(S)\\\\ {\;\;\;\;\;}K=\frac{1}{[O_2]^3\times1}=\frac{1}{[O_2]^3}$

$\text{The compounds that are not the part the equilibrium constant are}$

Fe Fe2O3

-----------------------------------------------------------------------------------

$\bf QUESTION\;3$

$\bf \text{ The active mass of } solids\text{ is taken to be }unity\text{ in the expression of equilibrium constant}$$\bf Ca_3(PO_4)_2(s)\rightleftharpoons 3Ca^{2+}(aq)+2PO_4^{3-}(aq)\\\\ {\;\;\;\;\;} K=\frac{[Ca^{2+}]^3[PO_4^{3-}]^2}{1}=[Ca^{2+}]^3[PO_4^{3-}]^2$

$\text{The molecules that are not the part the equilibrium constant are}$

$\LARGE \bf Ca_3(PO_4)_2$