Homework Answers
Ans 1 .
Reaction :
C3H8(g) + 5O2(g) <---> 3CO2(g) + 4H2O(l)
Standard Change in enthalpy of reaction
= deltaH°rxn = - 2220 KJ
As deltaH°rxn is negative , so , reaction is exothermic
And , Decreasing the temperature will result in increase the value of Keq and shift the equilibrium to the products side , that is , right side
Therefore ,
answer is a , shift the equilibrium to the right
1) 2) 3) 4) C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220...
1)
2)
3)
4)
C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A...
One of the components of smog is ozone,O3, a colorless, toxic gas. It is a very...
One of the components of smog is ozone,O3, a colorless, toxic gas. It is a very strong oxidizing agent and causes respiratory illnesses. Ozone is produced in the lower atmosphere due to the catalytic effect of nitric oxide, NO, a byproduct of the combustion process in car engines. However, in the upper atmosphere ozone is a very useful gas, because it absorbs ultraviolet radiation and protects the earth from this high energy, damaging radiation. It is referred to as the...
Ozone decomposes to molecular oxygen: 2 O3(g) ⇋ 3 O2(g). The following is a proposed mechanism...
Ozone decomposes to molecular oxygen: 2 O3(g) ⇋ 3 O2(g). The
following is a proposed mechanism for the reaction:
Step 1: O3(g) ⇋ O2(g) + O(g) (fast) Step 2: O3(g) + O(g) ⇋ 2
O2(g) (slow)
Provide a valid rate law for the overall ozone decomposition
reaction based on this mechanism.
4. Ozone decomposes to molecular oxygen: 203(g) — 3 O2(g). The following is a proposed mechanism for the reaction: Step 1: 03(g) – O2(g) + O(g) (fast) Step 2:...
Consider the following equilibrium reaction. P4S3(g) + 8O2(g) = P4010(s) + 3SO2(9) AH = -3677 kJ...
Consider the following equilibrium reaction. P4S3(g) + 8O2(g) = P4010(s) + 3SO2(9) AH = -3677 kJ If heat is removed from an equilibrium mixture of P4S3, P4010, O2, and SO2, then O Keq will decrease. the system will remain at equilibrium with no change in concentrations. the system will shift toward reactants to re-achieve equilibrium. O the system will shift toward products to re-achieve equilibrium. more information is needed to determine the effect on the equilibrium.
5. Chlorine destroys the Earth's ozone layer by the following precess. CI + O3 → CIO...
5. Chlorine destroys the Earth's ozone layer by the following precess. CI + O3 → CIO +02 ClO + O → Cl +O2 The O atoms in the second step come from the decomposition of ozone by sunlight: A. What is the net reaction for these three steps? B. What is the role of the chlorine atoms? C. Are there any intermediates? If yes, identify
QUESTION 21 A proposed mechanism for the decomposition of ozone in the atmosphere is: Step 1:...
QUESTION 21 A proposed mechanism for the decomposition of ozone in the atmosphere is: Step 1: 03(g) + hv → O(g) + O2(g) Step 2: O(g) + O3(g) → 202(0) Does this reaction mechanism have an intermediate and/or catalyst? Only a catalyst Only an intermediate An intermediate and a catalyst More information is needed O Neither an intermediate nor a catalyst
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values...
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values for reactions at 25°C, what is AH at 25°C for the following reaction: C3H3(g) + 502(g) + 4H2O(g) + 3CO2(g) AH = -2043 kJ 3C(s) + 4 H2(g) → C3H8 (g) 2H2(g) + O2(g) + 2H2O(g) AH° = -483.6 kJ
Consider the mechanism below. Step 1: O, (g) + Br (g) BrO (g) + O, (g)...
Consider the mechanism below. Step 1: O, (g) + Br (g) BrO (g) + O, (g) Step 2: Bro (g) + O (g) Br (g) + 0 (s) Overall Reaction: 03 (g) +O (g) → 2 02 (g) The catalyst in this reaction is a) O3 b) BrO c) Br d) O2 6.
Question 3 For the reaction 2 H20 (1) = 2H2(g) + O2(g), the equilibrium expression is:...
Question 3 For the reaction 2 H20 (1) = 2H2(g) + O2(g), the equilibrium expression is: [H21 [012 Keat H2012 O keq = [H-012 Keq = [H212 (02) Kea (H212 [02] H2012
AH = -727 kJ Given that CH3OH (1) + 3/2 O2 (g) → CO2 (g) +...
AH = -727 kJ Given that CH3OH (1) + 3/2 O2 (g) → CO2 (g) + 2 H2O(1) CO(g) + 1/2O2 (g) → CO2 (9) CH3OH(1) → CH3OH(g) AH = -284 kJ AH = 38 kJ H20 (1)→ H20 (9) AH = 44 kJ what is AH, in kJ, for the reaction CH3OH (g) + O2(g) →CO (g) + 2 H2O (9)
1)
2)
3)
4)
C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A...
Ozone decomposes to molecular oxygen: 2 O3(g) ⇋ 3 O2(g). The
following is a proposed mechanism for the reaction:
Step 1: O3(g) ⇋ O2(g) + O(g) (fast) Step 2: O3(g) + O(g) ⇋ 2
O2(g) (slow)
Provide a valid rate law for the overall ozone decomposition
reaction based on this mechanism.
4. Ozone decomposes to molecular oxygen: 203(g) — 3 O2(g). The following is a proposed mechanism for the reaction: Step 1: 03(g) – O2(g) + O(g) (fast) Step 2:...
Consider the following equilibrium reaction. P4S3(g) + 8O2(g) = P4010(s) + 3SO2(9) AH = -3677 kJ If heat is removed from an equilibrium mixture of P4S3, P4010, O2, and SO2, then O Keq will decrease. the system will remain at equilibrium with no change in concentrations. the system will shift toward reactants to re-achieve equilibrium. O the system will shift toward products to re-achieve equilibrium. more information is needed to determine the effect on the equilibrium.
5. Chlorine destroys the Earth's ozone layer by the following precess. CI + O3 → CIO +02 ClO + O → Cl +O2 The O atoms in the second step come from the decomposition of ozone by sunlight: A. What is the net reaction for these three steps? B. What is the role of the chlorine atoms? C. Are there any intermediates? If yes, identify
QUESTION 21 A proposed mechanism for the decomposition of ozone in the atmosphere is: Step 1: 03(g) + hv → O(g) + O2(g) Step 2: O(g) + O3(g) → 202(0) Does this reaction mechanism have an intermediate and/or catalyst? Only a catalyst Only an intermediate An intermediate and a catalyst More information is needed O Neither an intermediate nor a catalyst
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values for reactions at 25°C, what is AH at 25°C for the following reaction: C3H3(g) + 502(g) + 4H2O(g) + 3CO2(g) AH = -2043 kJ 3C(s) + 4 H2(g) → C3H8 (g) 2H2(g) + O2(g) + 2H2O(g) AH° = -483.6 kJ
Consider the mechanism below. Step 1: O, (g) + Br (g) BrO (g) + O, (g) Step 2: Bro (g) + O (g) Br (g) + 0 (s) Overall Reaction: 03 (g) +O (g) → 2 02 (g) The catalyst in this reaction is a) O3 b) BrO c) Br d) O2 6.
Question 3 For the reaction 2 H20 (1) = 2H2(g) + O2(g), the equilibrium expression is: [H21 [012 Keat H2012 O keq = [H-012 Keq = [H212 (02) Kea (H212 [02] H2012
AH = -727 kJ Given that CH3OH (1) + 3/2 O2 (g) → CO2 (g) + 2 H2O(1) CO(g) + 1/2O2 (g) → CO2 (9) CH3OH(1) → CH3OH(g) AH = -284 kJ AH = 38 kJ H20 (1)→ H20 (9) AH = 44 kJ what is AH, in kJ, for the reaction CH3OH (g) + O2(g) →CO (g) + 2 H2O (9)
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