Given , mass of N2O = 57.6 g
molar mass of N2O = ( 2 x 14 ) + 16 = 44 g/mol
so, number of moles of N2O = Mass / molar mass = 57.6 / 44 = 1.309 mol = n
volume = V = 4.86 L
temperature = T = 113 degree celsius = 386.15 K
R = 0.0821 L atm mol-1K-1
so, by ideal gas equation ,
PV = nRT
so, P = [ 1.309 X 0.0821 X 386.15 ] / 4.86 = 8.538 ~ 8.54 atm = pressure
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Question 21
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