N2(g) + 3H2(g) → 2NH3(g) | What is the limiting reagent in this reactant mixture? 1:2225:13...

Question

Question

Answer 1

Answer #1

Balanced chemical equation;

N2(g) + 3H2(g) >>>> 2NH3(g)

1 mol of N2 (blue) reacts with 3 moles of H2(white) completely.

Moles of N2 available = 6 mol

Moles of H2 available = 6 mol

For 6 mol N2 we require = (3mol-H2/1mol-N2)×6mol-N2 = 18 moles of H2(white) , for complete reaction.

But as as we have only 6 moles of H2(white) available, thus H2 is the limiting reagent.

H2 is the limiting reagent.

Answer 2

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