Question

14.0 g of acetylsalicylic acid were obtained from 23.9 g of salicylic acid.

Determine the percentage yield of acetylsalicylic acid.

What I did: 23.9 g ÷ 138 g = 0.1732 mol

Known Information:

Reactant mass: 23.9 g

Product mass: 14.0 g

Reactant moles: 0.1732 moles

*Please help: How would I solve for the Theoretical maximum moles of acetylsalicylic acid?

acetylsalicylic acid C₉H₈O₄ (12•9) + (1•8) + (4•16) = 180 g/mol

Would it be 14.0 g ÷ 180 g? Please explain.

Answer 1

23.9 gm tag salicylic acid Ca HoO3 molar malt : 138 g/mol moles of Salicylic acid - 23.9 g 0.17319 mol TOH сон ) salicylic quid I mol 0.17319 salicylic acid mol will produces produce 1 mol 0.17319 acetylsalicylic acid mol acetylsalicylic acid theoretical yield of acetylsalicylic acid 0.17319 mol mass = (0.17319 mol) (180 8 ml - 31.174 gm (theoritical yield y %. yield = actual yielel theoritical yield = x 100 14.0 gm 31.174 gm - 44.9%.