Question

10. Explain what is expected to happen to the optical activity to the reaction solution shown beld when the reaction is compl

for question 10, there would be 2 different form of product, and how to decide the optical activity?

and also, what determines optically active to inactive?

also, no idea how to deal with question 11

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Answer #1

Q1)) This reaction proceeds by SN1 mechanism. As the carbocation intermediate is planar , can be attacked from either side of the plane leading to both enantiomers in almost equal quantity. Thus we get an almost equimolar mixture of enantiomers called racemic mixture which does not show any optical activity[ due to external compensation].HO racemic mixture no (zero) optical rotation polas solvent solvent - Weak Nu SN[SOLYOLYSIS] the OTS de Sloco non backside l

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