Question

Calculate the empirical formula of a compound containing 47.3% Cu and 52.7% CI? Cu Cl2 CUCI Cu2C1 CuCl2

Answer 1

Molecular weight of cu is 63.546 g/mol Molecular weight of ce is 35.453 g /mol for chi Molecular weight of cu, eu, - 163.54682) + (35.45342)} Almal - 199.998 almal Here, weight of copper x = 163.54672) a = 127.092 g But, according to the question weight of copper, y = (194.918 x 473) a - 92.65 g So, here 24+ i for Culli Molecular weight of cult = (63.546 +35,453) almal = 98.999 7 1 mel Here, weight of copper, x2 = 63.546 g But, according to the question, weight of copper, 12 = (98.999 & 47.3) a = 46.826 g So, here, x2 = 42 for celli Molecular weight of cuzel = [(63.546*2) + 35. 4537 almal F = 162.545 & Imal Here, weight of copper, xz = (63.54672) a = 127.092 But, according to the question, weight of copper, 43 = (162.5 45 x 47 = 76.883 g So, here, x3 + 73 for Cult: Molecular weight of cuch, = [63.546 + (35.453 X2 g/ras = 134. 452 olmal Here, weight of copper, xy = 63.5468 100

But, according to the question, weight of copper, A = (134.452 x 47.3) a = 63.595 g ~ 631546 g = xy and, weight of chlorine, = 1134.452 x 527) a = 70.856 g.

And, here weight of chlorine = (35.45382) a - 70.9069 ~ 70.856 g Hence, the emperical formula will be [4th culla option is right here]