Question

Consider the following Bronsted-Lowery acid-base reaction: HC1O2 + N(CH3)3 = [HN(CH3)3]* +C102 Which two substances represent Bronsted-Lowery bases in this reaction? a HC1O2 and [HN(CH3)31* O b. N(CH3)3 and [HN(CH3)31+ c. N(CH3)3 and C102 d. (HN(CH3)3]* and C102 e HCIO2 and N(CH3)3

Answer 1

Aus Acc to Bronsted- lowry Acid theory- An Acid is a substance that donates Ht whereas Ht is known as the substance that accept Brousted Lowry base. Here we have - HClO2 + N(CH3)3 ² [HN(CH3)₂ + cuor - It is clear from the forward reaction that a HUO2 is donating it and N(CH3)3 accepts that proton, thus, N(CH3)3 - Bronsted Lowry base - from reverse reaction it is also clear that (HN(CH3)3]" donates 4t and cos is accepting that pooton, thus, coi » Bronsted Lowery base Hence, option (c) N(CH3)3 of cor is CORRECT Please Rate ...