Question

Read the experiment and answer the following questions as directed by your instructor. 1. Write the equilibrium reaction and the equilibrium expression for the dissociation of acetic acid in water reaction: equilibrium expression: K. = 2. Identify the Bronsted-Lowry acid and the conjugate base in the reaction from #1. Explain what the difference is between these two species. 3. Draw the Lewis structure of acetic acid, and label the hydrogen atom that is removed during the equilibrium dissociation. 4. If, when acetic acid is dissolved in water, the [H3O+] - 1.2 x 10", what is the C,H,O2]? If the equilibrium (HC2H30:] = 0.075, then what is the value of K.? 5. Write the equilibrium reaction and the equilibrium expression for the dissociation of acetate ion in water. reaction: equilibrium expression: Ks = 6. Identify the Bronsted-Lowry base and the conjugate acid in the reaction from #4. Explain what the difference is between these two species.

Answer 1

.) CHCOOH + Heu) e come onest Hemine ka= [CH608 ] [48] KO - [chcoot 2) Bronsted-bacury and = Proton donor is an acid. Aud and base which are difter by one protons are called as conjugate acid-beuse pair Chicoolt -> CH,Coo and conjugate base 3) Lewis structure of acetic and :: I loi e 1-¢-C-0-H - H--ö-Ö: + He Illu At equilibrium CHCOOH THO - Choo Hoo [elt coo] = [42.] ka= [chycool] [1280] [ch cook] = (1-2%70°) Ci-2x103) 0.015 51192x105 5) CH, Cost Hou cuccoti yt otion [cl,cool ] [or] [chlycoo] 6) Bronsted -lowry base = CH₂coo These two are differ by one proton Conjugate acid = citycoon J kbs