Question

Problem Set 14 November 4, 2019 CHEM 1252 Textbook Reading Assignment: 15.1-4 Additional Practice Problems: 15.11-15.12.19.21,24,28-31,35,37,4 . Acetic acid (HCOH) has 1.8 10-5 and acetate (HCO) has (a) Write balanced chemical equilibrium equations (with physical state acetic acid and base hydrolysis of acetate lon. 15.11-15,17,19,21,24,28-31,35,37,41,43,45,47 acetate (HCO") has = 5.6 x 10-10, $(with physical states) for acid dissociation of (b) Write K, and equilibrium constant expressions for the above reactions (c) Use your expressions from part b to show that KX-1.0 10-14 - [H3O+][OH). 2. For each of the following species. write a balanced chemical equation for its reaction with water, and calculate K, or for its conjugate acid or base from the information given. (a) CO32-, Ks = 1.8 x 10-4 (b) NH,OH (hydroxylamine), ks = 1.1 x 10- (c) CsHsNH(pyridinium), K. - 5.88 x 10-6 3. Calculate (OH). (H)POH, and pH of a 0.0020 M Ba(OH)2 Solution at 25 °C. FIGURE 15.10 LIC . grease and hair clogs from water pipes Tysically contain high concentrations of OH) = -log (1.2) = -0.079

Answer 1

Hello, i am sorry to say that as per HOMEWORKLIB RULES experts can answer only one full question that too first question or first 4 sub-parts like a), b), c) & d) only. I request you to please post remaining question as separate one since my allotted time could not permit me to answer more than one question also. Thank you in advance for your continued support to us.

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1a)

acid dissociation: CH₃COOH (aq) + H₂O (l) <==> CH₃COO^- (aq) + H₃O⁺ (aq)

base hydrolysis: CH₃COO^- (aq) + H₂O (l) <==> CH₃COOH (aq) + OH^- (aq)

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1b)

K_a = [CH₃COO^-][H₃O⁺] / [CH₃COOH] = 1.8 x 10^-5

K_b = [CH₃COOH][OH^-] / [CH₃COO^-] = 5.6 x 10^-10

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1c)

K_a x K_b = [CH₃COO^-][H₃O⁺] / [CH₃COOH] * [CH₃COOH][OH^-] / [CH₃COO^-]

[CH₃COOH] & [CH₃COO^-] terms cancel out

K_a x K_b = [H₃O⁺][OH^-] = [1.8 x 10^-5][ 5.6 x 10^-10] = 1.0 x 10^-14

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