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Problem Set 14 CHEM 1252 November 4, 2019 4. At 25 °C, K= 1.0 x 10-14, while at 0 °C, K= 1.2 x 10-15 (a) Explain whether wate

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Pure watr is always nutral lbecause in eah case But as tamperature decreasos, the 11 degree of onisation of watr decreases anAt oc, uw = CH301LOH CH30= LOH] = K = 2X1015 2 * 1015 3.46410M) at 25c 2.5 x 1 LOH = 2.5 x ID M) |x ו%, LOH - -logLH=-og (4x

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