The balanced equation is
NaOH + HA ----------> H2O + NaA
Volume of NaOH = 21.00 mL = 0.021 L
Number of moles of NaOH = M*V = 0.300 M * 0.021 L = 0.0063 mol
According to balanced equation,
1 mole of NaOH reacts with 1 mole of HA
So, 0.0063 mol of NaOH would react with 0.0063 mol of HA
Number of moles of HA = 0.0063 mol
Mass of HA = 0.500 g
Molar mass of the acid = mass/moles = 0.500 g/ 0.0063 mol = 79.36508 g/mol
Molar mass of
the acid = 79.37 g/mol
.500 g of a solid white acid are dissolved in water and completely neutralized by the...
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