7. A 0.653 g of a monoprotic solid acid (mw= 157 g/mol) is dissolved in water...
1. A weak monoprotic acid has molar mass 180 g/mol. When 1.00 g of this acid is dissolved in enough water to obtain a 300 mL solution, the pH of the resulting solution is found to be 2.62. What is the value of Ka for this acid? 2. A weak monoprotic acid has pKa = 3.08. Calculate the percent ionization of a 0.35 M solution of this acid. 3. Calculate the pH of a solution that is 0.050 M in CH3COOH...
12.22 g of the monoprotic acid KHP(MW = 204.2 g/mol) is dissolved into water. The sample is titrated with a 0.85 M solution of calcium hydroxide to the equivalence point. What volume of base was used?
Following the Procedure of this experiment, a student titrated 0.653 g of an unknown weak, monoprotic acid with 0.100 M NaOH and monitored the titration with a pH meter. His titration data were: Volume of NaOH solution added, mL /// pH 0.00 | 3.30 2.00 | 4.22 4.00 | 4.55 6.00 | 4.76 8.00 | 4.92 10.00 | 5.06 12.00 | 5.18 14.00 | 5.29 16.00 | 5.40 18.00 | 5.51 20.00 | 5.62 22.00 | 5.74 24.00 | 5.88...
Enough of a monoprotic acid is dissolved in water to produce a 1.06 M solution. The pH of the resulting solution is 2.56. Calculate the K, for the acid. Number If the K of a monoprotic weak acid is 7.1 x 10 what is the pH of a 0.40 M solution of this acid? Number PH- The K of a monoprotic weak acid is 2.57 x103. What is the percent ionization of a 0.178 M solution of this aci Number
A) The Ka of a monoprotic weak acid is 2.29 × 10-3. What is the percent ionization of a 0.129 M solution of this acid? I got 104.8% which I know is impossible. B) The Ka value for acetic acid, CH3COOH(aq), is 1.8× 10–5. Calculate the pH of a 2.40 M acetic acid solution. C) Calculate the pH of the resulting solution when 4.00 mL of the 2.40 M acetic acid is diluted to make a 250.0 mL solution. I...
A 100.0 mL solution containing 0.956 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.350 M KOH. Calculate the pH of the solution after the addition of 47.0 mL of the KOH solution. Maleic acid has pKa values of 1.92 and 6.27 pH At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H,M, HM, and M2, which represent the fully...
a. Enough of a monoprotic acid is dissolved in water to produce a 0.0163 M solution. The pH of the resulting solution is 2.51. Calculate the Ka for the acid. Ka= ________ It's not 5.86 10-4. I tried it and it wasn't correct. b. The Ka of a monoprotic weak acid is 6.61 × 10-3. What is the percent ionization of a 0.108 M solution of this acid? Percent ionization= ___________ it's not 24.72 %. I tried it's also incorrect.
A 100.0 mL solution containing 0.750 g of maleic acid (MW=116.072 g/mol) is titrated with 0.264 M KOH. Calculate the pH of the solution after the addition of 49.0 mL of the KOH solution. Maleic acid has pKa values of 1.92 and 6.27. pH= At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H2M, HM−, and M2−, which represent the fully protonated, intermediate,...
1.800 g of N-2-acetamido-2-aminoethane-sulfonic acid potassium salt (ACES–K , MW = 220.29 g/mol) is dissolved in 89.94 mL of water. 29.91 mL of HCl is added to the solution, resulting in a pH of 7.24. Calculate the concentration of the HCl solution. The pKa of ACES is 6.85.
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0183 M solution. The pH of the resulting solution is 2.47. Calculate the pKa for the acid.