Question
part 1
A mixture of 0.03771 mol of H70, 0.02921 mol of CH 0.05732 mol of Co, and 0.05598 mol of Hy is placed in a 10-L steel pressur
part 2
Consider the reaction given below. H2(g) + F2(g) → 2HF(G) (a) Using thermodynamic data from the course website, calculate AG
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Answer #1

+ - H₂O(g) 0.03771 1 CH4 (91 0.02921 Initial COCGI+ 34₂ (9) 0.05732 0.05598 ta +33 Change na Equilibriu 0.05598 + 31. 0.03771- -chy Total males 0.01158 . 0.21548 0.054. Xo = 0.348 0.07495 0.21548 0.10887 0.505 0.21548 - Partial pressure - Total press

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