Question

In relation to M(acac)3 complexes, assuming they contain an octahedrally coordinated M3+ ion:

Draw the ligand field orbital diagrams for Co(III), Fe(III), Mn(III), and Cr(III) to derive the possible electron configurations for the metal complexes.

State the number of unpaired spins each configuration has.

Which is the correct d-electron configuration for each complex? Which complexes are "high spin" and which are "low spin"?

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Answer 1

Generally Co (11) complexes are low sypin complexes except When the ligands are very weak field Egi cor 73-t lát ahogy e are the only two lige spin complexes of co(11) But all other colui compleness are rond splu so Cola cac) z is a low spin complen ww, for an as acac ligand is a wear Sield ligame to the metals except Co Cill generally gives we un cum complines ie; high spin complines. Here fe (M), Mal Gives High spin complen. . Grcli) in a d3 syslemm Here it is noted the High spin / Low spin complen only possible for ds.dt so (r(!!!) sives same electron arrangement irrespective a ligand. ligono field diagrams: ~ Co (11) : do for de_d7 system a possible - eg (daryt, dar) 1 1 1 1 1 1 ... IV V V tag (day, duz, dy z) Law spin complen. No of unpaired electron = 0. ind-electron configuration - tag eg Feuil) und ey High Spin Complen No of unpairede is . confign: ny eg2 1 1 I za My (111) :-04 1 1 1 1 my ubin pter No of unpairede 4 1 Confign: ty eq 1 1 1 1

& Bt d3 No of superrede :3 onba tag eg A Ang . Collui) forms and spin complia. Felun & Me Cun form high spin complex Co (1) gives 30 electrons su orbits diassam.