Specific heat of water is 4.184 J/goC
As we know , the specific heat of water is the amount of heat required to increase the temperature of 1 gram of the substance to 1 oC.
So to increase the temperature of 32.5gm of substance to (35.22 - 24.73) = 10.49 oC , putting the formula Q= MC∆T
where M is the mass of the substance.
C is the specific heat of water.
∆T is the temperature difference.
Heat required = 32.5 × 4.184 × 10.49 = 1426.43J .
So 1426.43J of energy is required to increase the mass of M=32.5gm of substance of temperature 35.22 oC to 24.73 oC .
How much energy is required to raise the temperature of 32.50 g of water from 24.73...
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