Question

/ 11Balance the following equation using they reaction method in acid. H(aq) + NO2 (aq) →z(s) + NO (8) Balancing Redox rxns using a rxn me thod : a urite the oxidahon half rxh and the redox half rx seperately ] Balance all elements except Oxygen and hydrogen. © Balance oxygen using H, Ở Balance hydrogen using H+ © Balance charge w/e's 6 multiply rans by integers so the es gained = es lost Add 12 runs, subhact things that appeur on both sides

Answer 1

Q) Balance the following equation using the ya real method in acid. I aq) + Noz ceg) 128 + Nog Step 1: Breaking down the reaction into 2 half reaction Img) → Izc Noz (ag) — Ngg Step2 : Balance all elements except oxygen & hydrogen 27203 126) ; Nožeq) —> Nogs here nithogen atom is abready balanced, therefore no change. Steps : Balance oxygen using H2O 2 .269Izo ; Noz dag) → NO + H20 Does not contain oxygen atom, therefore remains 00 as such

Step 4 : Balance hydrogen using H+ 2 Tagh) > Phone F26) ; 2H+ + Noz @q) Noge + H20 Does not contain Hydrogen atom, therefore equation Memains as such. Step 5: Balance charge with electrons 21.09.) → I20+2ē ; zē + 2H+ + Noz > Nog) + H20 (aq) Step 6 : Multiple ya reactione by integers so the electrons gained = electrons lost. *Abueady the eleccions are balance, therefore the 2 equatione remains as such, 200) — I2037 22 ; zē + 2H+ + Notag] → Nog) + H2O Step 7 : Add y, reactions, substract things that appear on both sides 210 93 — 1269 + zé Zé + 24*+ NB (eng- Nog + H20 2 Iep) + 2H+ + NOzcaq) –> I2.4.+ N@gyt H2O

Balanced chemical equation:

217aq) + 2H+ + NO3(aq) — 13+ NO + H20