Question

47. (3) How many grams of ozone (Os) must decompose to produce 0.87 g of oxygen? (oxygen is the only product, ozone is the only reactant) a. 0.87 b. 1.3 c. 0.58 d. 1.67

Answer 1

Using: Molar mass of oxygen = 32 g/mol Molar mass of ozone = 48 g/mole Calculate the moles of oxygen formed as follows: Moles of oxygen = mass/molar mass = 0.87/32 mole The balanced chemical reaction from ozone to oxygen is as follows: 203 → 302 Then 2 moles of ozone produce 3 moles of oxygen. Calculate the moles of ozone decompose as follows: Moles of ozone decompose = Moles of oxygen/1.5 Moles of ozone decompose = (0.87)/(32*1.5) moles Calculate the mass of ozone decompose as follows: Mass of ozone = moles*molar mass Mass of ozone = {(0.87)/(32*1.5)}*48 = 0.87 grams. Therefore, option a is the correct answer. Please give good Rating.