8)
a)
we have:
[A]o = 0.52 M
[A] = 0.12 M
t = 150.0 min
use integrated rate law for 0 order reaction
[A] = [A]o - k*t
0.12 = 0.52 - k*1.5*10^2
k = 2.667*10^-3 min M/min
Answer: 2.7*10^-3 min M/min
b)
Given:
k = 2.667*10^-3 M/min
use relation between rate constant and half life of 0 order
reaction
t1/2 = [A]o/(2*k)
= 0.52/(2*2.667*10^-3)
= 97.5 min
Answer: 97.5 min
Only 1 question at a time please
8. In the reaction A products the initial concentration of A is 0.52M and the concentration...
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