A converging lens creates the image shown in:
Is the object distance less than the focal length f, between f and 2f, or greater than 2f?
between f and 2f
because the image real and inverted.
from the figure, magnifocation, m = -1.5
-v/u = -1.5 (here u and v are object and images distances)
v = 1.5*u
now use,
1/u + 1/v = 1/f
1/u + 1/(1.5*u) = 1/f
(1/u)*(1 + 1/1.5) = 1/f
1.67/u = 1/f
==> u = 1.67*f
so, f < u < 2f
A converging lens creates the image shown in: Is the object distance less than the focal...
For what position of the object will a converging lens not project an image on the screen? a) At a distance greater than twice the focal length b) Between the focus and the lens c) At a distance equal to twice the focal length d) Between the focus and a distance of twice the focal length.
(a) Find the object distance (in terms of f) for a thin converging lens of focal length f if the image is real and the image distance is seven times the focal length. (Use any variable or symbol stated above as necessary. Enter your coefficient to two decimal places.) p = (b) Find the object distance (in terms of f) for a thin converging lens of focal length f if the image is virtual and the absolute value of the...
You could not see the image of the text when the lens to object-distance was less than the focal length, but you could see it when it was equal to or greater than the focal length. What does this tell you about the eyes ability to process diverging rays, parallel rays, and converging rays?
Question 24 A converging lens creates an image of the object shown in the diagram. The object is further from the lens than the case (A) object focal point. In case (B), a region on one side of the lens airair is filled with water a) I you are in the water in case (B) case (B), where will the i mage appear to be from object your perspective (compared to case (A) closer to the lens, at the s...
(a) The relation between the object distance S, the image distance S' and the focal length f of a lens producing a real image is given as 1 1 1 S S This is called the Gaussian form of the thin lens formula. Another form of the formula, the Newtonian form, is obtained by considering the distance x, from the object to the first focal point and the distance x; from the second focal point to the image. Show that...
An object is a distance 16.9cm to the left of a converging lens ("Lens 1") with a focal length of 20cm. Lens 1 is itself a distance 30cm to the left of a second converging lens ("Lens 2") with a focal length 20cm. The object is along the optical axis of the two-lens system. What is the magnification of the image due to Lens 1? If the image is inverted your answer should be negative, and if it is upright...
Q9. Finish the following ray diagram such that the object is in front of a converging lens with a distance of more than f but less than 2f. The distance between the lens centre to one of its neighbour black dot is fthe focal length. After finishing the ray diagram, tell me: a. Is the image real or virtual? b. Is the image upright or inverted? c. Is the image size enlarged or reduced?
An object is placed to the left of a converging lens of focal length f = 30 cm, such that the object-to-image distance is 7 cm. Find the magnification.
An object is placed to the left of a converging lens of focal length f = 30 cm, such that the object-to-image distance is 7.5 cm. Find the magnification.
A 6 mm high object is placed 48 cm to the left of a converging lens with focal length 12 cm. 1) The image distance will be: Less than -20 cm Between 0 and 20 cm Greater than 20 cm Between 0 and -20 cm 2) The magnitude of the image height will be: Between 6 and 9 mm Between 3 and 6 mm Less than 3 mm Greater than 9 mm A 6 mm high object is placed 10...