Question

A 6 mm high object is placed 48 cm to the left of a converging lens with focal length 12 cm.

1) The image distance will be:

Less than -20 cm

Between 0 and 20 cm

Greater than 20 cm

Between 0 and -20 cm

2) The magnitude of the image height will be:

Between 6 and 9 mm

Between 3 and 6 mm

Less than 3 mm

Greater than 9 mm

A 6 mm high object is placed 10 cm to the left of a diverging lens with focal length -15 cm.

1)The image distance will be:

Greater than 15 cm

Less than -15 cm

Between 0 and 15 cm

Between 0 and -15 cm

2) The magnitude of the image height will be:

Between 6 and 9 mm

Between 3 and 6 mm

Less than 3 mm

Greater than 9 mm

Answer 1

f = 12cm uz 48 Cha TO F 12cm K 48cm using lens formula & - - - - ---- 12-48 va 16cm Hence, image distance wes between magnifreation (m) - v 16 - 48 himho o and doch 2 > u hi m - -2mm Hence, height of image is less than 3mm using lens formula 1 = (v=-6cm 1. V - 4 1 1 +1 -10 V Hences between o and -15cm image distance lies magnification (m) =) u m = 0.6 mho hi Ri = 0.6x6 hi 3.6 mm height lies between 3 and 6 mm