Question

An object 1.7 cm high is placed 41.9 cm to the left of a lens having...

An object 1.7 cm high is placed 41.9 cm to the left of a lens having a focal length of 28.9 cm.

A) Is this lens converging or diverging?

B) Find the location of the image produced by this lens.

c)Is the image inverted or upright?

d) What is the height of the image? (only positive numbers here, even if the image is inverted)

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
An object 1.7 cm high is placed 41.9 cm to the left of a lens having...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length o...

    An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...

  • A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal...

    A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual

  • An object 2.00 cm high is placed 45.3 cm to the left of a converging lens...

    An object 2.00 cm high is placed 45.3 cm to the left of a converging lens having a focal length of 40.3 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position cm magnification...

  • 11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of...

    11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...

  • Now, a diverging lens with focal length having a magnitude of 20 cm is placed 10...

    Now, a diverging lens with focal length having a magnitude of 20 cm is placed 10 cm to the right of the converging lens in problem that has a 2 cm tall object placed 12 cm to the left of a converging lens with focal length of magnitude 15 cm. Determine the location of the final image formed by both lenses (in relation to the diverging lens) and the magnification of the final image. State whether the final image is...

  • A 1.00-cm-high object is placed 3.25 cm to the left of a converging lens of focal...

    A 1.00-cm-high object is placed 3.25 cm to the left of a converging lens of focal length 7.15 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.

  • A 4-cm tall object is placed 59.2 cm from a diverging lens having a focal length...

    A 4-cm tall object is placed 59.2 cm from a diverging lens having a focal length of -29.5 cm. a) Is the image produced by this lens virtual or real? b) Is the image inverted or upright? c) Is the image on the same side of the lens as the object or on the opposite side as the object? d) Where is the image located? (Please provide the magnitude of the position, no negative numbers) e) How tall is the...

  • A 4.0 cm tall object is placed 50.0 cm from a diverging lens having a focal...

    A 4.0 cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 20.0cm. a. What is the location of the image? b. What is the magnification of the image? c. Is the image inverted or upright? d. Is the image virtual or real?

  • 2) A diverging lens is placed 20. cm away from an object, 80. cm from the...

    2) A diverging lens is placed 20. cm away from an object, 80. cm from the diverging lens is a converging lens whose focal length is 25 cm. 35. cm from the converging lens is a screen showing an image of the object. a) What is the focal length of the diverging lens? f = 25. cm o *20. cm → 80. cm + 35 cm → b) What type of image is it? Circle one Real or Virtual c)...

  • A real object is 13.6 cm to the left of a thin, diverging lens having a focal length of magnitude 24.5 cm.

    A real object is 13.6 cm to the left of a thin, diverging lens having a focal length of magnitude 24.5 cm. (a) is the sign of the focal length negative or positive? negative positive (b) Find the image distance. (c) Find the magnification. (d) State whether the image is real or virtual. real virtual (e) State whether the image is upright or inverted. upright inverted

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT