Question

REPORT FORM: REGIOSELECTIVE BROMINATION OF ACETANILIDE Balanced Equation(s) for Main Reaction(s): Brz Hjc Coche 4 И В Balanced Equation(s) for Important Side Reactions): compound MW mg or ml mmol acetanilide B5.17 95 mg 6. 25 ml bromine 159.22 p-bromoacetanilide 214.07 Indicate the limiting reagent with an asterisk (*). Product Observed melting point range: 160.0.4480 Literature melting point range:167.169 °C Molecular weight of product: 214.07 Theoretical yield: Experimental yield: g Percent yield: 95 %

can someone help please!!!

Answer 1

NH-Co-Ciltze Bra. 19= loco my Itys Igns. les H₂C-Coolt Acetanilide Hot: 135.17 g hole P-Bromo peetaniüde Coo = Oro 1993. glrole helst :2 14.06 rot Hole weight (9) Motoleo rolexiood compound weight (lon meg (glroce) rest I 0.095 Acetanilice 135.199lheid 135.17 = 0.060 7028 0.zole 95 My 00 0.0959 0.25 HV Bra 70.7754 159.8089ltade 0.60484 ५.१५ 1509 Elu 814.06 SIP-Broko I Acetanilide / 01150g 0.0007028 0.7028 12 Bro weight = Density x volune 3 301% 0-25 = 0.7759 :. Among the two Reactant Acetanilide Number of roles. Thus Acetani lide is has in the limitina Reagent. 1/1

calculation of theoretical yield (toot yield): 135.17 gry of Acetanilide producer 214.06 948 of 4-Born Acetanidade . 0.095 ghg of Acetanilide produces ? Sng of U-Bato Acetanilide - 0.0954214.06 135.17 gry of 44- Brotto Acetani lide - 01 (5 g Theoretical gield 0.150 ang

calculation of Experitiental yield (SHS): t of yilld: Experimental Yield (ang --- X loo theoretical yield (GHI) 95% = Experimental yield (ons) X loo 0.150 Experimentar yield (948) = 95X0.150 . 100 = 0.1485 9HS. :: Experimentas yilld = 0.1425 ghee