The combustion of ethane is given as
C2H6 (g) + 7 O2 (g) --> 4 CO2 (g) + 6 H2O (g)
The rate of formation of carbon dioxide is 0.80 M/s
1) + 1/4 [CO2] / t = + 1/6 [H2O] / t
[CO2] / t = 0.80 M/s
[H2O] / t = 6/4 [H2O] / t
[H2O] / t = 6/4 (0.80)
[H2O] / t = 1.20 M/s
2) 1/4 [CO2] / t = - 1/7 [O2] / t
[O2] / t = - 7/4 [CO2] / t
[O2] / t = -7/4 (0.80)
[O2] / t = - 1.40 M/s
3) 1/4 [CO2] / t = - [C2H6] / t
[C2H6] / t = - 1/4 (0.80)
[C2H6] / t = - 0.20 M/s
The combustion of ethane is given as C2H6 (g) + 7 O2 (g) --> 4 CO2...
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