Balance the equation for the complete combustion of ethane: C2H6 (g) + O2 (g) ⟶⟶CO2 (g) + H2O (g). Calculate ΔΔHofor the reaction per mole of ethane using the given bond dissociation energies.
The balanced reaction is:
2 C2H6(g) + 7 O2(g) —> 4 CO2(g) + 6 H2O(g)
On reactant we have:
12 C-H bond
2 C-C bond
7 O=O bond
On product we have:
8 C=O bond
12 O-H bond
So,
Delta H = BE(reactant) - BE(product)
= 12*BE(C-H) + 2*BE(C-C) + 7*BE(O=O) - 8*BE(C=O) - 12*BE(O-H)
= 12 * 413 + 2*347 + 7*498 - 8*799 - 12*467
= -2860 KJ
Answer: -2860 KJ
Balance the equation for the complete combustion of ethane: C2H6 (g) + O2 (g) ⟶⟶CO2 (g)...
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