Homework Answers
1)
On reactant side we have:
4 C-H bond
2 O=O bond
Sum of BE(reactant) = 4*BE(C-H) + 2*BE(O=O)
= 4*413 + 2*498
= 2648 KJ
Answer: 2648 KJ
2)
On product side we have:
2 C=O bond
4 O-H bond
Sum of BE(products) = 2*BE(C=O) + 4*BE(O-H)
= 2*799 + 4*467
= 3466 KJ
Answer: 3466 KJ
3)
Use:
Delta H = BE(reactant) - BE(product)
= 2648 KJ - 3466 KJ
= -818 KJ
Answer: -818 KJ
= 6*BE(C-H) + 2*BE(C-O) + 3*BE(O=O) - 4*BE(C=O) - 6*BE(O-H)
= 6*414 + 2*360 + 3*498 - 4*707 - 6*464
= -914 KJ
Answer: -914 KJ
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