Using the table of bond energies below, calculate the following enthalpy values associated with this reaction:...

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Using the table of bond energies below, calculate the following enthalpy values associated with this reaction: 2 HF (g) H2 (g

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Answer 1

Answer #1

On reactant side we have:
1 H-H bond
1 F-F bond

On product side we have:
2 H-F bond

1)
Sum on reactant = 1*BE(H-H) + 1*BE(F-F)
= 432 + 159
= 591 KJ
Answer: 591 KJ

2)
Sum on product = 2*BE(H-F)
= 2*565
= 1130 KJ
Answer: 1130 KJ

3)
Delta H = BE(reactant) - BE(product)
= 591 KJ - 1130 KJ
= -539 KJ
Answer: -539 KJ

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Answer 2

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