Question

Estimate the enthalpy of formation of HF from the following bond energies: (twenty-five points) H2 (g)...

Estimate the enthalpy of formation of HF from the following bond energies: (twenty-five points)
H2 (g) + F2 (g) → 2 HF (g)

Bond: H-H =432KJ/mol

F-F=159 KJ/mol

H-F= -565 KJ/mol

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Answer #1

H₂ + f→ 2HF A4 = reactent bond enogy - product bond ency H=Ht for - 2x Hof - 434+159- (2x565) [1721 KI/mol

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