H2(g)+F2(g) ----> 2 HF(g) ; dH = -269 KJ
dH = bond energy of reactants - bond energy of products
-269 = H H-H + H F-F - ( 2* H H-F)
-269 = 432KJ + H F-F - (2*565 KJ )
H F-F = 429 KJ/mol
Using the table of bond energies below, calculate the following enthalpy values associated with this reaction: 2 HF (g) H2 (g)F2 (g) Bond type Bond Energy (kJ/mol) 159 F-F H-H 432 H-F 565 Enter your answers to zero decimal places. Ignore significant figure rules. Include negative signs if necessary What is the sum of the reactant bond enthalpies? kJ What is the sum of the product bond enthalpies? kJ What is the overall enthalpy of reaction? kJ
Estimate the enthalpy of formation of HF from the following bond energies: (twenty-five points) H2 (g) + F2 (g) → 2 HF (g) Bond: H-H =432KJ/mol F-F=159 KJ/mol H-F= -565 KJ/mol
Use bond energies, values of electron affinities, and the ionization energy of hydrogen (1312 kJ/mol) to estimate AH for the following reaction Bond Energies Electron Affinities H-F (565 kJ/mol) F() (-328 kJ/mol) H-CI (427 kJ/mol) C1(9) (-349 kJ/mol) -(295 kJ/mol) 1(9) (-295 kJ/mol) 0_H(467 kJ mol) OH(g) (-180. kJ/mol) H2O(g) + H+ (g) + OH (9) AHL b HCI(g) + H+ (g) + CI" (9) AH = kJ
Use the bond energies given below to calculate the enthalpy change for the reaction, HCN(g) + 2 H2(g) → CH3NH2(g) Bond Bond Energy (kJ/mol) Bond Bond Energy (kJ/mol) H-H 432 C-H 413 C-N 305 C=N 615 C:N 891 N-H 391
the enthalpy change in a chemical reaction can be determined using bond energies. energy must be added or absorbed to break bonds and that energy is released when bonds are formed. therefore ,you can calculate the total enthalpy of the reaction using following formula: dH= bonds broken-bonds formed Using bond energies, calculate the change in energy that accompanies the following reaction: H2 + O2 -> 2H2O Bond Bond Energy H-H 432 kJ/mol O-O 498 kJ/mol H-O 467 kJ/mol
The enthalpy change for the following reaction is 95.4 kJ. Using bond energies, estimate the N-H bond energy in N2H4(g). N2(g) + 2H2(g) N2H4(g) kJ/mol The enthalpy change for the following reaction is -92.2 kJ. Using bond energies, estimate the H-H bond energy in H2(g). 2NH3(g) N2(g) + 3H2(g) kJ/mol D Single Bonds Multiple Bonds C N O F Si P S a Br 1 H 436 413 391 463 565 318 322 347 C 413 346 305 358 485...
Name: Quiz 9 CHE 1030 1. Using the following bond energies Bond Energy (kJ/mol) 839 413 495 799 467 Bond C-H O-0 C-O O-H estimate the heat of combustion for 1 mol of acetylene: C2H2(g)+ O2(g) → 2CO2(g)+H2O(g) 2. Using the following data reactions: H2(g) + Cl2(g) → 2HCl(g) H2(g) → 2H(g) Cl2(g) 2CIg) AP (kJ) -184 432 239 calculate the energy of an H-Cl bond.
Which of the following statements are FALSE, given the following bond dissociation energies? Assume that bond energies accurately determine heats of reaction. Check all that are false. BE[H-H] = 436 kJ/mol BE[H-N] = 393 kJ/mol BE[H-O] = 460 kJ/mol BE[O=O] = 499 kJ/mol 1. NH(g) + H2(g) ---> NH2(g) + H(g) is an exothermic reaction. 2.ΔH°f[H(g)] = 218 kJ/mol 3. ΔH°[H2O(g) ---> 2 H(g) + O(g)] = 920 kJ/mol 4. An H-H bond is stronger than an H-O bond. 5....
Use the given bond enthalpy data to estimate the Ho (kJ) for the following reaction. (C - H = 414 kJ, H - F = 565 kJ, C - Cl = 331 kJ, C - F = 439 kJ, F - F = 157.8 KJ). CH3Cl(g) + F2(g) =>CH2FCl(g) + HF(g)
8. Given the following bond dissociation energies, what is the AF" for the formation of hydrogen chloride? H2(g) + Cl2(g) → 2 HCI(g) Bond Energy (kJ/mol) Bond 436 243 432 H-H Cl-CI H-Cl A) 185 kJ/mol. B) -92.5 k.J/mol. C) 92.5 kJ/mol. D) -185 kJ/mol.? E) 277.5 kJ/mol.