1)enery of products-energy of reactants
(2*799)+467-{ 839 +(2*413)+(2.5*495)}
enrgy of formation is -837.5
2)similarly
product-reactants=energy of formation
products =energy of formation +reactanats
solving we get HCL bond enegy is 487
Name: Quiz 9 CHE 1030 1. Using the following bond energies Bond Energy (kJ/mol) 839 413...
Bond Energies and Heat of Reaction Use the given bond energy values to estimate AH for the following gas-phase reaction. H2N + HN_NH, + H2N— NH2 - * | - + HO Học HAC CH H₃C CH₂ (Simple energy units required for the answer.) 142 kJ D-values in kJ/mol DH-H = 432 DH-Br = 363 DH-C = 413 DH-N = 391 DH-o = 467 Dc-c = 347 DC=C = 614 Dec = 839 DC-N = 305 DC-N = 615 DCEN...
Bond Energies and Heat of Reaction Use the given bond energy values to estimate AH for the following gas-phase reaction. HC= CH - CH + HN HCC HC— CH HC=CH NỮ NH. + HC cỮch Cáo + HẠO HC- CH NH2 HON (Simple energy units required for the answer.) -454 kJ D-values in kJ/mol DH-H = 432 DH-Br = 363 DH-C = 413 DH-N = 391 DH-O = 467 Dc-c = 347 DC-C = 614 DCEC = 839 DC-N =...
Use bond enthalpies (in kJ/mol): C-C 348 C=C 614 C≡C 839 H-H 436 C-H 413 O-H 463 C-O 358 C=O 799 to estimate ΔH for the reaction H2C=CH–CH2–OH (g) = > HC≡C–CH=O(g) + 2 H2(g)
Using the bond energies from the table below estimate ∆H for the following reaction C2H2(g) + H2(g) → C2H4(g) C-H (413), H-H (436), C-C (348), C=C (614), C≡C (839) A) +165 kJ/mol B) -390. kJ/mol C) +390. kJ/mol D) –124 kJ/mol E) –165 kJ/mol
The enthalpy change for the following reaction is 95.4 kJ. Using bond energies, estimate the N-H bond energy in N2H4(g). N2(g) + 2H2(g) N2H4(g) kJ/mol The enthalpy change for the following reaction is -92.2 kJ. Using bond energies, estimate the H-H bond energy in H2(g). 2NH3(g) N2(g) + 3H2(g) kJ/mol D Single Bonds Multiple Bonds C N O F Si P S a Br 1 H 436 413 391 463 565 318 322 347 C 413 346 305 358 485...
the enthalpy change in a chemical reaction can be determined using bond energies. energy must be added or absorbed to break bonds and that energy is released when bonds are formed. therefore ,you can calculate the total enthalpy of the reaction using following formula: dH= bonds broken-bonds formed Using bond energies, calculate the change in energy that accompanies the following reaction: H2 + O2 -> 2H2O Bond Bond Energy H-H 432 kJ/mol O-O 498 kJ/mol H-O 467 kJ/mol
Bond Dissociation Energies (for A-B Bond broken AH, kJ/mol Bond broken → A A4, kJ/mol + B) Bond broken mo H-H CH3CH2CH2-H (CH3)2CH-H (CH3)3C-H 436 423 413 400. H-Br 366 CH3CH2CH2-Br 294 (CH3)2CH-Br 298 (CH3)3C-Br292 Br-Br 193 H-CI 432 CH3CH2CH2-CI 354 (CH3)2CH-CI 355 (CH3)3C-CI 349 CI-CI 243 Alkane halogenation is a two-step reaction, as shown below. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. Step 1: Number CH3CHCH3...
7) Use the bond energies (kJ/mol) to calculate the heat of reaction: C-O 799 N-H: 391 C-N 3050-H: 467 O=C=0 + 2NH 8) Acetic acid is produced in the reaction between methanol and carbon monoxide: H-C-0-H + C=O- Use bond energies (kJ/mol) to calculate the enthalpy of reaction. C-O: 358 C-H: 413 0-H: 467CEO: 1070 C-C: 347 C=0: 745C-O: 358
Use the given bond energy values to estimate AH for the following gas-phase reaction. H2N. CH3 НАС, + H20 HC CH CH | HỌC CH, CH3 (Simple energy units required for the answer.) 912kJ D-values in kJ/mol DH-H = 432 DH-Br = 363 DH-C = 413 DH-N = 391 DH-O = 467 Dc-c = 347 Dc=c = 614 Dcæc = 839 DC-N = 305 DC=N = 615 DcEN = 891 DC-o = 358 Dc=0 = 745 DC=O (CO2) = 799...
Using the table of bond energies below, calculate the following enthalpy values associated with this reaction: Co2 (g)2 H20 (g) CH4 (g)+2 02 (8) Bond type Bond Energy (kJ/mol) C-C 347 C=C 614 C-H 413 O-O 204 498 O=O 358 C-O C=O 799 H-O 467 Enter your answers to zero decimal places. Ignore significant figure rules. Include negative signs if necessary. What is the sum of the reactant bond enthalpies? kJ What is the sum of the product bond enthalpies?...