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Using the standard enthalpy of formation data, show how the standard enthalpy of formation of HF(g) can be used to determineAverage Bond Enthalpies bondAH bond (kJ/mol) bond AHbond (kJ/mol) bond AH bond (kJ/mol) bond AH bond (kJ/mol) O-H 0-0 467 146

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The formation of HF is given as follows: H2(g)+F(8) → 2HF(g) For 1 mol of formation of HF, the reaction is written as, H, (8)

answered by: ANURANJAN SARSAM
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