Use bond energies to estimate the enthalpy of formation of HBr(g). BE(H–H) = 436 kJ/mol BE(Br–Br)...

Question

Question

Use bond energies to estimate the enthalpy of formation of HBr(g).
BE(H–H) = 436 kJ/mol
BE(Br–Br) = 192 kJ/mol
BE(H–Br) = 366 kJ/mol

A –52 kJ/mol

B +262 kJ/mol

C +104 kJ/mol

D +52 kJ/mol

E –104 kJ/mol

Answer 1

Answer #1

Answer 2

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