Question

Given the reaction below: N2O4(g)→2NO2(g)N2O4(g)→2NO2(g) d) You increase [NO2][NO2], but change nothing else about the system....

Given the reaction below:

N2O4(g)→2NO2(g)N2O4(g)→2NO2(g)

d) You increase [NO2][NO2], but change nothing else about the system. How will this affect the value of K?

Select one:

a. K will decrease.

b. K will increase.

c. K will not change.

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Answer #1

N ₂ Oyly) - 2N02 K= No 272 N2oy K only depends here charge Nog does not on temperature charge & c) I will not charge.

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Given the reaction below: N2O4(g)→2NO2(g)N2O4(g)→2NO2(g) d) You increase [NO2][NO2], but change nothing else about the system....
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