Homework Answers
NaClO is conjugate base of HClO
So, its pH would be more than 7
C5H5NHBr is conjugate acid of C5H5N
So, its pH would be less than 7
KCH3CO2 is conjugate base of CH3CO2H
So, its pH would be more than 7
C6H5NH3Cl is conjugate acid of C6H5NH2
So, its pH would be less than 7
C6H5NH3Cl is stronger acid as compared to C5H5NHBr because Kb of
C5H5N is more.
So, pH of C6H5NH3Cl will be less than pH of C5H5NHBr
NaClO is stronger base as compared to KCH3CO2 because Ka of
CH3CO2H is more.
So, pH of NaClO will be more than pH of KCH3CO2
Answer:
NaClO: 4
C5H5NHBr: 2
KCH3CO2: 3
C6H5NH3Cl: 1
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