Answer
solution | pH |
0.1M C6H5NH3Cl | 1 |
0.1M NaClO | 4 |
0.1M KNO3 | 3 |
0.1M NH4Br | 2 |
Explanation
i) C6H5NH3Cl and NH4Br are salts of weak base and strong acid , so their solutions would be acid due to partial dissociation of conjucate acids , C6H5NH3Cl and NH4Br
C6H5NH3+ (aq) + H2O(l} <-------> C6H5NH2(aq) + H3O+(aq)
NH4+(aq) + H2O(l) <----------> NH3(aq) + H3O+(aq)
C6H5NH2 is less basic than NH3 , C6H5NH3+ is more acidic than NH4+
ii) KNO3 is a salt of strong acid and strong base , so the solution of KNO3 would be neutral
iii) NaClO is salt of weak acid and strong base ,so solution of NaOCl is basic due to partial hydrolysis of conjucate base OCl-
OCl-(aq) + H2O(l) <----------> HOCl(aq) + OH-(aq)
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