Question

Suppose that you massed out 3.50 g of sodium carbonate, Na2CO3. How many moles would you have? *

Answer 1

Dear student, kindly refer to solution.

Dear Student, Given, LO mass of sodium carbonate Na2CO3 = 3.50g molecular mass of sodium carbonate Na, co 1 = 2 (atomic mass) + (atomic mass) of ra of C + 3 ( atomic mass of) = 2 ( 33 g/mas) + (1291 met) + 3 (1691 mel) = 106 pimel Moles of Na, co = mass of Na₂CO3 molecular mass of MacO₂ 3.50 g 106 g/mol = 0.03302 moles Best wishes !!