33) How many moles of sodium carbonate are in a sample of pure sodium carbonate that contains 14.33 grams of sodium ions?
Moles of sodium = mass / molar mass
= 14.33 / 23
= 0.623
Formula of sodium carbonate = Na2CO3
So, 2 moles are consumed for 1 mole of Na2CO3
So moles of Na2CO3 will be 1/2 of Na
= 1/2 * 0.623
= 0.3115
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33) How many moles of sodium carbonate are in a sample of pure sodium carbonate that contains 14.33 grams of sodium ions...
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