Calculate the Enthalpy of a reaction
C + 1/2 O2 -----> CO2 , delta H = -110.3 kJ/mol
CO + 1/2 O2 -----> CO2 , delta H = -283.2 kJ/mol
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C + O2 -----> CO2 , delta H = [x] kJ/mol
Calculate the Enthalpy of a reaction C + 1/2 O2 -----> CO2 , delta H =...
1. Using the reactions given below please calculate the change in enthalpy (delta H) for the stated reaction. Stated Reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) delta H = ?! Given Reactions & Enthalpy Changes: 2 Fe(s) + 3/2 02(g) → Fe2O3(s) 2 Fels) * delta H = -824.2 kJ delta H = -282.7 kJ CO(g) + 4 02(g) → CO2(g) 2. Using the reactions given below please calculate the change in enthalpy (delta H) for...
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
[32] The enthalpy of reaction for [6] enthalpy of reaction for the combustion of C to CO, is-393.5 kJ/mol C, and the enthalpy for the combustion of CO to CO, is-283.0 kJ/mol CO: (i) C(s) + O2(g) + CO2(e) AH -393.5 kJ CO(g) + O2(g) + CO2(g) AH -283.0 kJ Using these data, calculate the enthalpy for the combustion of C to CO. (iii) C(s) + O2(g) - CO(g) AH-?
calculate delta H for the reaction C(diamond)=C(graphite) given the following data C(diamond)+O2(g)=CO2(g) deltaH=-395.45kJ C(graphite)+O2(g)=CO2(g) delta H= 393.5kJ deltaH=
7. The enthalpy of combustion of C to CO2 is –393.5 kJ/mol C, and the enthalpy of combustion of Co to CO2 is -283.0 kJ/mol CO: C(s) + O2(g) + CO2(g) AH = -393.5 kJ CO(g) + 102(9) CO2(g) AH = -283.0 kJ Using these data, calculate the enthalpy of combustion of C to CO: C(s) + O2(g) → CO(g) AH = ? Answer: -110.5 kJ
given the following reaction caco3(s)--->cao(s) + co2(g) delta h = 178.1kj C(s,graphite) + O2(g) ---> CO2(g) deltaH=-393.5kj the enthalpy of the reaction CaCO3(s)--->CaO(s) + C(s,graphite) + O2(g) is ________kj.
Use the Data table to calculate ∆H for the reaction below:Reactions: Change in Enthalpy (∆H)(1) C (s) + O2 (g) -> CO2(g) ∆H1 = -393.5 kJ/ mol(2) H2 (g) + 1/2 O2 (g) -> H2O (l) ∆H2 = -285.8 kJ/mol(3) 2C2H6 (g) + 7O2 (g) -> 4 CO2 (g) + 6 H2O (l) ∆H3 = -283.0 kJ/molCalculate the enthalpy change for the reaction:2 C (s) + 3 H2 (g) -> C2H6(g) ∆H = ______________kJ/mol
From the following enthalpy changes in equations (1) and (2), calculate the heat of reaction for equation (3). (1) C(s) + 1/2 O2 (g) → CO (g) ΔH°= -110.5 kJ (2) CO (g) + 1/2 O2 (g) → CO2 (g) ΔH°= - 283.0 kJ (3) C(s) + O2(g) →CO2(g)
8.) From the values of delta H and delta S, calculate delta G then predict whether the following reactions would be spontaneous or not at 25 C. a) Reaction A: delta H= 10.5 kJ/mol, and delta S = 30 J/K mol b) Reaction B: delta H=1.8 kJ/mol, and delta S = -113 J/K mol 9.) Calculate the delta G and K, for the following equilibrium reaction at 25 C: 2H2O(Ⓡ) <-> 2H2(g) + O2(8) delta Gran H2O(x) = -228.6 kJ/mol
Find the enthalpy change for the reaction CS2(l) + 3 O2(g) → CO2(g) + 2 SO2(g) when: C(s) + O2(g) → CO2(g) ΔHf = -393.5 kJ/mol S(s) + O2(g) → SO2(g) ΔHf = -296.8 kJ/mol C(s) + 2 S(s) → CS2(l) ΔHf = 87.9 kJ/mol