Question

a) How many atoms are in 92.2 g of pure aluminum?

b) How many grams of carbon, C, would contain the same number of atoms as 39.948 g of argon, Ar?

c) How many grams of S are in 785 g of SO2?

Answer 1

Given mass of AL= 9202g. Molar maes of Al= 2791neol. moles of al = 92.26 = 3.4mol - tglie Atoms = 3.4 not x 6.02x10 23 atons No. of ato me = 2006x10²4 atom, nou

Given mass of Ar= 39.948z. Molas mass of Ar= 39.948 g / mole molee of Ar= 39.9488 Inol - 39.9487 free! moles of a required = Imola . mass of c required a molar may ofc - 12 q lns l _ .. mass = 1292 معععطعوا مي امیل های دره ع mass of so2 = 785g of so, present = F85g moles z 12.26 molar . Mase - mass more of s= 32g|mo| of s = 12:26 motx 3 29 (not of s = 392 59.
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