Calculate the equivalence point in the titration of 20.00 mL of 0.1252M HCl with 0.1008M NaOH.
I know we have to do:
20ml ( 0.1252M ) = 2.5mmol
But I dont understand why we have to divide 2.5 mmol over .1008M . Im trying to understand the concept so I can understand how to do other problems similar to this one. So if someone can explain that would be very helpful :)
There is molarity equation used for this.
Calculate the equivalence point in the titration of 20.00 mL of 0.1252M HCl with 0.1008M NaOH....
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