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How many grams of NO will be produced from 60.7 g of No, reacted with excess water in the following chemical reaction? 3 NO2

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3 NO2 & Molar H₂O -> 2 HNO3 & No (excess) NO2 = 14 + 2x16 - 46 Ilmole No = 14+ 16 = 30 g/mole mass : from chemical reaction:

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