Concepts used to solve:
· To calculate molar mass of a compound, add the atomic masses of each component atom.
· Equ1: No of moles =
· To find how much substance is produced or consumed, always compare the number of moles from the balanced chemical reaction. (don’t compare masses, or volumes, or concentrations).
16)
Balanced reaction :
3NO2 (g) + H2O (l) = 2HNO3 (aq) + NO (g)
a.
From the reaction, we see that 1 mole H2O will give 1 mole NO.
So, 2.0 moles H2O will give 2.0 moles of NO.
b.
65g of HNO3 is formed. Molar mass of HNO3 = 63g/mol
Using equ1, no. of moles of HNO3 = = 1.03 moles
From the balanced equation, 2 moles HNO3 is formed from 3 moles NO2
Thus, 1.03 moles HNO3 is formed from = 1.545 moles NO2.
Mass of NO2 (molar mass = 46g) (using equ1) = 1.545 moles x 46g/mol = 71.07g
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