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Question 8 (1 point) Electrons will be ejected from the surface of the metal molybdenum (Mo) by photons of 274 nm or less. Wh
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Answer #1

Answer: 7.25*10^-19 joule

Minimum energy required(E) = hc/l

E = ? joule

h = planks constant = 6.625*10^-34 j.s

C = light velocity = 3*10^8 m/s

l = maximum wavelength = 274 nm = 2.74*10^-7 m

E = (6.625*10^-34)*(3*10^8)/(2.74*10^-7)

E = 7.25*10^-19 joule

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Answer #2
7.249×10^-23
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