Answer: 7.25*10^-19 joule
Minimum energy required(E) = hc/l
E = ? joule
h = planks constant = 6.625*10^-34 j.s
C = light velocity = 3*10^8 m/s
l = maximum wavelength = 274 nm = 2.74*10^-7 m
E = (6.625*10^-34)*(3*10^8)/(2.74*10^-7)
E = 7.25*10^-19 joule
Question 8 (1 point) Electrons will be ejected from the surface of the metal molybdenum (Mo)...
When 289-nm photons are incident on the surface of a metal, electrons are ejected from it and the stopping potential is 2.69 V. Find the energy of incident photons: E,= (4.287 eV. Find the kinetic energy of ejected electrons: K= eV. Find the work function of the metal: p= 1.597 ✓ev. Find the wavelength of the least energetic photon that can induce the photo- electric effect in this metal 2 = 778 nm.
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plz answer all Fois Molybdenum metal must absorb radiation with a minimum frequency of 1.09 x 10" - before it can emit an electron from its surface via the photoelectric effect Part A What is the minimum energy needed to produce this effect? % AEO , Submit Request Answer at wavelength radiation will provide a photon of this energy? V AXP om? sk16 ac_ch01_...xlsx Lopes sk16 ....accdb ^ SK16 AC CH...docx ^ HV ALDO VW Constants Periodic Ta ? Submit...
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