Question

Methamphetamine has a biological half life of about 20 hours. How will it take (in hours) to have 90% of the meth cleared from a drug addict? Assume first order kinetics

Answer 1

K. Answer for first ander Kinetics Alt) = Ao ekt and Ti= 0.693 where Alt)= Concentration at time t o 40. Initial concentration K2 Rate Constant Tya half life time ginen Tigo 2ohu. So 20 hours 0.693 K = 0.693 646 20 hour ellek: 0.03465 howe? - Now, if 904 of meth gat cleared, it means only 10% of meth left het original concentration of meth = Ao Then Alt) = 10% of Ao = 10 x to = 0.1 Ao Cod Ao = Ao e-kt of ekt ental) = -kt ln (0.1) 0.03465 haut + - Ấn (3.1) so of it will mith to take get nearly cleared. 66 hours