Question

can anyone help with this

EZ Data and calculations grams it iodine 1.849479 moles iodine grams in a start] 1.592g Lgrame tin at end 1.5749 dams tin ved 0.018 molestina ratto, moles I moeisn empirical formula name of compound 1.61419 mass of filter paper plus produet mass of filter paper mass of product 0.42939 1.1848

Answer 1

Solution:

solution Determination of formula step 1. Giren data: 1 mass of iodine = 1.84947 g ii) mass of sn at start = 1.5929 ii) mass of sn unreacted = 0.4073g. (V) mass of sn reacted = 1 18 480 v mass of product = 1.57 380 step 2: xon + Yty compound contains In and convert mass into mole Snity I mot of 1 molt 1 = 1.84947 qx- J 1.84947 26.90 126.90g Tatomic weight of t = 126.90 0.01457 mol mol of sn = 1.18480 g x 1 mol sn. 118.71g Abomie weight of sn= 118.7 10 18 480 11871 = 0.009980 mol step 3: find a ratio by dividing each element mol by smallest amount of mol. 0.01457 mol of! - 1. 4867 empirical formula. 0.00980 Sn, I 1.4867 and 0.009980 mol of sn sno 0.00980 step: multiplying by a common factor to get whole number I = 1.4867 X 2 = 2.97 n 3 in = 1 X 2 = 2 Thus formula must be Sn, Iz

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