Question

For these calculations, obtain the data shown on the previous page for two other groups. Make calculations here using your data and the data from the two other groups. Average Moles of Magnesium (mol) 10.014+0.016870.0169/3 LE00150 Standard Deviation in Moles of Magnesium (mol) 0.00165 Average Moles of Oxygen (mol) (0.017+0.00770.000649/3 = 0.008214 Standard Deviation in Moles of Oxygen (mol) 10,0082 Mole Ratio of Magnesium to Oxygen Calculations (Show all calculations used to produce the above data here.) 1. Calculate the mass of oxygen from the total mass of the magnesium oxide compound formed. 2. Calculate the mole ratio of the magnesium to oxygen: 3. Calculate the empirical formula for the magnesium oxide compound: 4. Calculate the standard deviation in the class measurements for the magnesium and oxygen:

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Answer 1

47.2539 41.966 47.7779 42.206 g. I G2 from Giren data, Own data man of crucible (g) 1 41.354 g. 41.613.9. 2) May of ing. (g) 41.695-41.354=0.341 0.409 g 0.410g. mass of crucible with I contents after rean (9) A man of Magnesium oxide 41.966-41.354 149.377 - 47.253 49.206 - 41.613 (3-0) (g) = 0.6129 = 0.524 9. ' = 0.593.9 6 Mass of oxygen in 10.612 - 0.341 0.524 - 0.409 0.593 - 0.410 Magnesium oxide (9) = 0.271g. 1 = 0.1159. i 0-18.3 g. =C - ] © Moles o Magnesium 0.410 1 a man of mg = 0.017 mol 0-409, 0-017 mol 0.0142 mol 0.341 ②/24 mol wt of mg. | 34 24 0-183 0.115 0.017 molto 0.007 moll - 0.011 mol moles of oxygen mg, ch Очеn. S molwlofo 16 = 16 16

3 firemnige man of mg - 0.341 +0.409 +0.4109 turbo = 0.387 9 Avriage mall of magnesium oxide formed: 0.612 + 0-524 40.593. Lig - 0.586g. 3 frocage man of oxygen = 0.576-0-387 = 0.189 g. Muringe moles of Mg = 0.0144 + 0.019 +0.015 mol = 0.048 mol = 0.016 standard dev.ation in molu of | (0.04 -0.016)+(0.019 -0.016) - VOOR D016) 3 E (x-7) to-002)² + (0.001) ²410001² 0.0000 04 + 0.000001 +0.000001) 3 0.000006 3x10 1. UID 0.0014 males Alverage mole of 0 0.019 + 0.0001 +0.011 0.035 = 0.0116 2 0.01 moles standard deviation in moles of i= -x) = -- ( 09-0-012) + (c-007.001 (DID (0.005) + (-0.005) + (0 OC)? = 0.000051 - = 4.12X10° 0. do y moly

· ind to o Mg = 00142 Ma = 0-014 .1 mg 0-017 = 2.4 0.017 Mg = 0.017: 105 O. DIY | 0 0.017 - 1.2 milo: 0-007 0.007- O 0:00 0.014 ) 00 Dou Forqerial fourruda. Mg, o, Img 2.40 (multiply by mg 1.50 1 = Mg ₂02 (multiply by = mg sa L o calculate And Mass of man of oxygen : ö from Mau of total mass a Mg Oxide magnesium oxide formed a formed man of mg taken = 0.5769 - 0.3879 = 0.189 gm. © mole ratio of mg to o Arg moles of mq = 0.016 mol - Arg moles of o= 0.012 mol mole ratio of mg to mole of mg/mdu o o o 016007 4 - moles of o/mola da 0.01%0.012 3 (3) : Emperical formula of Magnelium oxide formed a Mgu oz. ☺ loswer Puplanud