Question

please help me with the second column.

Lab Data Sheet 1. Mass of lid (9) Trial 1 6.66904 39.65269 40.29104 Trial 2 16.4783 38.0139 32.54279 2. Mass of crucible and

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Answer #1

So We are dealing with Trial 2

Mass of lid(g)

16.4783

Justification or formula

Mass of crucible and lid(g)

38.0039

Mass of crucible, lid, and Magnesium(g)

38.5422

Mass of crucible lid and compound_1st reading (g)

38.8118

Mass of crucible lid and compound_2nd reading (g)

38.8131

Mass of crucible lid and compound_ average of two reading (g)

=(38.8118+38.8131)/2

= 38.81245

Mass of magnesium(g)

0.5383

=( Mass of crucible, lid, and Magnesium- Mass of crucible and lid)

=(38.5422-38.0039)

Moles of Magnesium(mol)

0.02215

= mass of magnesium in g / molecular weight of magnesium in g

Molecular weight of magnesium = 24.305

so moles of magnesium = 0.5383/24.305

=

Mass of compound(g)

0.80855

=( Mass of crucible lid and compound_ average- Mass of crucible and lid)

=(38.81245-38.0039

=0.80855

Mass of oxygen in compound(g)

0.27025

=(mass of compound-mass of magnesium)

= 0.80855-0.5383

= 0.27025

Moles of oxygen in compound(mol)

0.00844558

= mass of oxygen in g/ molecular weight of oxygen in g

=0.27025/ 31.999

31.999 is molecular weight of oxygen(O2).

= 0.00844558

Mole ratio of magnesium to oxygen

2.6227

= moles of magnesium/moles of oxygen

=0.02215/ 0.00844558 = 2.6227

% mass of magnesium in compound

66.58

=(Weight of magnesium/compound mass) x100

=(0.5383/0.80855) x100 = 66.58

% mass oxygen in compound

33.42

=(Weight of oxygen/compound mass) x100

=(0.27025/0.80855) x100 =33.42

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