Question

chemistry simple empirical formula determination for magnesium oxide | waters of hydration determination | can I please get help finishing this lab? I'm at a loss

DATA SHEET- EXPERIMENT 3A Name: Simple Empirical Formula Determination for Magnesium Oxide Inal 1 Trial 2 42.037 g 43.861g 0.246 g 10.247 g 42.450 44.268 g 1. Mass of crucible and lid, g 2. Mass of magnesium at start,g: 3. Mass of crucible, lid and product, g: 4. Mass of product,g: 5. Mass of oxygen in product, g 16. Moles of magnesium in product: 7. Moles of oxygen in product: 8. Mole ratio, Mg:O: 9. Average mole ratio, Mg:0: 10. Probable simple empirical formula: Waters of Hydration Determination Triall Trial 2 42.997 g 41.014 g 11. Mass of crucible and lid, g: 12. Mass of crucible, lid & CuS04 xH20 start, g: 44.555g 44.510 g 1.557 g 1.496 g 43.975 g 41.945 g 13. Mass of CuSO4 - xH20 13. Mass of crucible, lid and CuSO4 end, g 14. Mass of water lost, 15. Mass of CuSO4,g: 16. Moles of water: 17. Moles of CuSO4: 18. Number of moles of water of hydration:

Answer 1

S.No.		Trail 1	Trail 2	Remarks
A	Mass of Crucible and lid, g:	42.037	43.861
B	Mass of Mg at Start, g:	0.246	0.247
C	Mass of crucible, lid and product, g:	42.450	44.268
D	Mass of product, g:	0.413	0.407	C - A
E	Mass of oxygen in product, g:	0.167	0.16	D-B
F	Molar ratio, Mg:O :	0.01 : 0.01 or 1:1	0.01 : 0.01 or 1 : 1	Divide the mass of Mg and O by their corresponding Atomic masses and simplify the ratio to whole number
G	Average Molar Ratio	1 : 1
H	Probable Simple Empirical Formular	MgO
Water of Hydration determination
I	Mass of Crucible and lid, g:	42.997	41.014
J	Mass of crucible, lid and CuSO4.xH2O start, g:	44.555	44.510
K	Mass of CuSO4 . xH2O, g:	1.557	1.496
L	Mass of crucible, lid and CuSO4 end, g:	43.975	41.945
M	Mass of water lost, g:	0.978	0.931	L - I
N	Mass of CusO4, g:	0.579	0.565	K - M
O	Moles of water	0.054	0.052	M / 18 (M. Mass of water)
P	Moles of CusO4	0.0036	0.0035	N / 160 (M. Mass of CuSO4)
Q	Number of moles of water of Hydration	CuSO4. 15H2O	Dividing the values in O and P by lowest values, we can simplify the ratio of CuSO4 : H2O